Alessandro Morita Enjoying the thermodynamic limit

Heat capacities only exist in one dimension

Recap

As commonly seen in textbooks, the heat capacity (at constant volume, say) is defined as

CV=(QT)V.C_V=\left(\frac{\partial Q}{\partial T}\right)_V.

This may look like an innocuous definition, but strictly speaking, it does not make sense. The heat QQ is not a state function; only the 1-form δQ\delta Q is well-defined, and it is not exact: there is no function Q~\tilde Q such that δQ=dQ~\delta Q = d\tilde Q globally.

However, this doesn’t seem to hinder thermodynamics. For example, in the case above, standard textbooks suggest the following procedure: since

dU=δQpdVdU = \delta Q - p dV

(at constant particle number), then at constant volume one finds (δQ)V=(dU)V(\delta Q)_V = (dU)_V: an exact differential. Hence, the heat capacity is found to be

CV=(UT)VC_V = \left(\frac{\partial U}{\partial T}\right)_V

and all is well - the right-hand side only involves proper state functions.

The question is then: can we always make this happen? When we fix a variable, say XX, will we always find

(δQ)X=(dF)X(\delta Q)_X=(d F)_X

for some function FF? If we do, then we heat capacity at constant XX is easily found to be

CX=(FT)X.C_X=\left( \frac{\partial F}{\partial T}\right)_X.

The issue in more than 1 dimension

Consider the equation defining a 1-form in 1D,

ω=f(T)dT\omega = f(T) dT

for an independent variable TT. This form is closed, since

dω=f(T)dTdT=0.d\omega = f'(T)dT \wedge dT = 0.

By the Poincaré lemma, it is also exact: there exists a function gg such that ω=dg\omega = dg. In fact, it is a pretty obvious one:

ω=dg(T)=f(T)dT    g(T)=Tf(T)dT.\omega = dg(T) = f(T) dT \implies g(T)=\int^T f(T') dT.

As long as ff is well-behaved (locally integrable), then the integral on the RHS is always well-defined. In other words: in 1D, all one-forms are exact.

Now, if we go to two dimensions, this is not the case anymore. Consider a 1-form

ω=f(T,V)dT+g(T,V)dV.\omega = f(T, V) dT + g(T, V) dV.

Then, its exterior derivative is

dω=(fV)TdVdT+(gT)VdTdV=[(fV)T+(gT)V]dTdV\begin{align*} d\omega &=\left(\frac{\partial f}{\partial V}\right)_T dV \wedge dT + \left(\frac{\partial g}{\partial T}\right)_V dT \wedge dV\\ &= \left[-\left(\frac{\partial f}{\partial V}\right)_T + \left(\frac{\partial g}{\partial T}\right)_V\right] dT \wedge dV \end{align*}

which, in general, will not be zero. This shows the expected result: in 2D (and higher), 1-forms are in general not closed.

What this means for heat capacity

From the discussion in the previous section, we conclude the following: for an equation of the form C=Q/TC = \partial Q/\partial T to be well-defined, it must be defined on a one-dimensional submanifold. In terms of thermodynamics, this means: impose constraints so that the thermodynamic process is restricted to a 1-dimensional submanifold, parameterized by TT.

Let us show two examples. For a general system with MM particle species, the first law of thermodynamics is

dU=δQpdV+i=1MμidNi.dU=\delta Q-p dV+\sum_{i=1}^M \mu_i dN_i.

Let us again consider the case of constant volume. Then, δQ\delta Q is a combination of dUdU and MM other terms; we still cannot make δQ\delta Q closed. Hence we need to fix more variables: fixing all the particle numbers, we finally get δQ=dU\delta Q = dU and hence

CV,N1,,NM=(UT)V,N1,,NM.C_{V,N_1,\ldots, N_M}= \left(\frac{\partial U}{\partial T} \right)_{V,N_1,\ldots, N_M}.

This is a proper definition. We could not have defined, say, heat capacity at constant volume alone, and let the particle numbers vary, unless they were somehow constrained by temperature; for example, if there was a deterministic procedure to set Ni=Ni(T)N_i = N_i(T).

For constant pressure, the procedure is similar, except one naturally starts with enthalpy H=U+pVH = U +pV:

dH=dU+pdV+Vdp=δQ+Vdp+i=1MμidNi.\begin{align*} dH &= dU + p dV + V dp\\ &=\delta Q+Vdp + \sum_{i=1}^M \mu_i dN_i. \end{align*}

By fixing, now, pressure and particle numbers, we find the usual expression

Cp,N1,,NM=(HT)p,N1,,NM.C_{p,N_1,\ldots, N_M}=\left(\frac{\partial H}{\partial T}\right)_{p,N_1,\ldots, N_M}.

Conclusion

We started by asking whether it is always the case that, by fixing a variable, we can make δQ\delta Q into an exact differential. The answer is: not one variable. We need to constraint enough variables so that we can fix the process to live on a 1-dimensional submanifold. When that happens, we can properly define the heat capacity.